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Derivatives, Calculus help?
Find an equation of the tangent line to the graph of y=f(x) at x= -3 if f(-3)=2 and f '(-3)=5
How can I do this problem? I feel like there isn't enough information?
1 Answer
Relevance
- 10 years ago
The question tells you that at the value x = -3, the slope is 5. Use the form y = mx + b where m is your slope 5 and be is your y-axis intercept. If f(-3) = 2 then f(-2) = 7, f(-1) = 12, and y intercept f(0)= 17.
Therefore, your equation is y = 5x + 17
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