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Log Question Help Needed (10points)?
0.1(x)^((logx)-2) = 100
I get to the point where I have x ^ logx and x ^-2 = 1000 but then I can't figure out what to do next.
Update:
Answer is 1000 and 0.1
Update 2:
Could you show the steps please?!
1 Answer
Relevance
- 1 decade agoFavorite Answer
logx = 1, -3.
log(0.1) + {logx - 2}log(x) = log100
-1 + {logx - 2}logx = 2
(logx)^2 - 2logx - 3 = 0
logx = [2 +/- sqrt (4 + 12)]/2 = 3, - 1.
x = antilog1, antilog(-3) = 1000, 0.1.
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