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Na2CO3 * __ H2O. Fill in the blank...?

Its a lab that I am doing.

Crucible + Lid : 37.18g

Crucible + Lid + Na2CO3 * _ H2O : 41.15g

Crucible + Lid + Na2CO3 : 39.54g

m of Na2CO3 * _ H2O : 3.97g

m of H2O : 1.61g

m of Na2CO3 : 2.36g

Moles of Na2CO3 := 2.36 / 105.99

= 0.0223 moles

Moles of H2o = 1.61 / 18.02

= 0.0893 moles

Ratio = 0.0893 / 0.0223

= 4

Am I right??

3 Answers

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  • Dr.A
    Lv 7
    1 decade ago
    Favorite Answer

    Yes you are right and the formula is Na2CO3 * 4H2O

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  • Anonymous
    1 decade ago

    Na2CO3.10 H2O it's called hydrated sodium carbonate (washing soda)

    idk how to get it from this problem,but it's constant and it can't be 4 :)

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