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A simple Pendulum word problem?

The square of the period of a pendulum, T varies directly with the length of the pendulum, L and inversely with the acceleration due to gravity, g.

a) Determine the equation for g.

b) Given the period of the pendulum to be 2.4s, for a pendulum length og 1.4m and a g value of 9.8m/s^2. Determine a value for k.

My work so far::

a) T^2 = kL

and

T^2 = k / Ag {Ag is accelation due to gravity}

Ag = k / (T^2)

b)

T^2 = k /Ag

2.4^2 = k / 9.8

56.448 = k

But the problem is the k value is no where close if I use the length in the first equation (T^2 = kL)..

Help?? :S

Update:

BTW k is the constant

2 Answers

Relevance
  • 1 decade ago
    Favorite Answer

    Actually, the equation is:

    T^2=(kL)/Ag ==>There is only one equation.

    a) Ag=(kL)/T^2

    b) 5.76=k(1.4)/9.8

    (5.76)x(9.8)/(1.4)=k

    k=40.32

    (Please check, I'm a little prone to carelessness...)

  • Anonymous
    1 decade ago

    Extra help

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