Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
I need help with a physics word problem?
I really need to know how to do this problem. The answer along with an explanation would be greatly appreciated!!
When Joe stepped up to the plate and hit a .150 kg baseball traveling at 36 m/s, the impact cased the ball to leave his bat with a velocity of 45 m/s in the opposite direction. If the impact lasted for 0.002 seconds, what force did Joe exert on the baseball?
1 Answer
- AlgolLv 71 decade agoFavorite Answer
the key is the change in mommentum. From this relation :
FΔt = Δp
Solved for F (average force) :
F = Δp /Δt
= [(0.15kg)(45m/s) - (0.15kg)(-36m/s)] / 0.002s
= 6.1kN (about 6100N)
Note that the approach of the ball to the bat is taken as negative.
Hope this helps.
