Can someone help me with factoring for math?

12u³+36u²+27u =

3u (4u² + 12 u + 9) =

*******

(a+b)² = a² + 2ab + b²

For a = 2u and b = 3:

(2u+3)² = 4u² + 12 u + 9

*******

so:

3u (2u+3)²

Kisses from Brazil

=**

Take out the common factor of the lot.

3u (4u^2+12u+9)

You now have 4u^2+12u+9, which is the perfect square of 2u+3

3u (2u+3)^2

Simple.... Tah-daah!!

First look for common factors in each term:

3u(4u^2 + 12u + 9)

Then check the trinomial, can it be factored ?

It is a perfect square trinomial:

3u(2u + 3)(2u + 3)

You need to review special products. Look in your text book and do more exercises.

12u³ + 36u² + 27u

3u (4u² + 12u + 9)

3u (2u + 3) (2u + 3)

3u (2u + 3)²

Answer: 3u (2u + 3)²

12u^3+36u^2+27u

3u(4u^2+12u+9)

3u(2u+3)(2u+3)

3u(2u+3)^2