Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
How can I calculate the trigonometric values of this triangle if I don't have the angle values?

2 Answers
- KrishnamurthyLv 74 weeks ago
Sin J = 3/5, cos J = 4/5, tan J = 3/4
Sin L = 4/5, cos L = 3/5, tan L = 4/3
- Daniel HLv 54 weeks ago
You only need 2 values to calculate all the other missing values. You have 3 values. The sides a=12,b=16,c=20
from corner L
cos(L) = a/c
sin(L) = b/c
tan(L) = sin(L)/cos(L) = b/a
from corner J
cos(J) = b/c
sin(J) = a/c
tan(J) = sin(J)/cos(J) = a/b
cos(L) = sin(J) = 12/20
sin(L) = cos(J) = 16/20
tan(L) = cot(J) = 16/12
tan(J) = cot(L) = 12/20
Not needed for the problem but:
L = arccos(12/20) = arcsin(16/20) = 53.1
J = arccos(16/20) = arcsin(12/20) = 36.9
L + J = 90