A cylinder with a moveable piston contains 216 mL of nitrogen gas at a pressure of 1.42 atm and a temperature of 293 K.?

(216 mL) x (1.42 atm / 1.52 atm) x (332 K / 293 K) = 229 mL

PV=nRT <<<memorize!!

n is moles, R is gas constant (use correct one!), T is temp in K (C+273.15)

Since you have a before and after with the same n &R simplifies to

PV/T initial = nR = PV/T final

Now sub in your numbers and solve

SI Units R values:

8.31446261815324 J⋅K−1⋅mol−1

8.31446261815324 m3⋅Pa⋅K−1⋅mol−1

8.31446261815324 kg⋅m2·K−1⋅mol−1s−2

8.31446261815324×103 L⋅Pa⋅K−1⋅mol−1

8.31446261815324×10−2 L⋅bar⋅K−1⋅mol−1

0.082057 L atm mol-1K-1

62.36L·torr/mol·K = L·mmHg/mol·K

P1V1/T1 = P2V2/T2

1.42 atm (216 mL) / 293K = 1.52 atm (V2) / 332 K

V2 = 229 mL