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If ABCD is a kite how can I find angle C, when consecutive sides are congruent? (DA=AB, DC=CB)?

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- AshLv 72 months agoFavorite Answer
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ADB forms isosceles triangle with AD ≅ AB
m∠ADB = m∠ABD ... (1)
In Δ ADB,
m∠ADB + m∠ABD + m∠A = 180°
from (1)
m∠ADB + m∠ADB + 120° = 180°
2m∠ADB = 60°
m∠ADB = 30°
m∠ADC = m∠ADB + m∠BDC
85° = 30° + m∠BDC
m∠BDC = 55°
Since DC ≅ BC
m∠DBC = 55°
In Δ DBC,
m∠BDC + m∠DBC + m∠C = 180°
55° + 55° + m∠C = 180°
m∠C = 70°
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