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? asked in Science & MathematicsPhysics · 3 months ago

6N force pushes to the right on a 3 kg mass for 8 seconds. How much momentum was gained?

48kg*m/s

2kg*m/s

0.5kg*m/s

or 0kg*m/s

3 Answers

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  • az_lender
    Lv 7
    3 months ago
    Favorite Answer

    a = 2 m/s^2, 

    delta-v = 16 m/s,

    delta-p = 48 kg*m/s.

    OR:  F = delta-p/delta-t =>

    delta-p = F delta-t = (6N)/(8 s) = 48 kg*m/s

  • Demiurge42
    Lv 7
    3 months ago

    There's not enough information  to determie how much momentum was gained.  It could even be losing momentum.

  • oubaas
    Lv 7
    3 months ago

    ΔP = ΔI = 6 N * 8 sec = 48 N*sec = 48 kg*m/sec 

    ΔV = ΔP / m = 48 kg*m/sec / 3 kg = 16 m/sec 

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