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When a force of 6 N is applied to a block of 2 kg mass, it moves along a horizontal surface at constant speed.?
(i) What is the force of friction?
[Answer: 6N]
(ii) When the force is increased to 10 N, what is the acceleration?
[Answer: 2 m/s2]
(iii) What is the speed, if it accelerates from rest for 10 s?
[Answer: 20 m/s]
Can someone show me how to do these questions please?
1 Answer
- ?Lv 74 months agoFavorite Answer
When a force F = 6 N is applied to a block m = 2 kg , it moves along a horizontal surface at constant speed
(i) What is the force of friction FF ?
FF = module of F = 6 N with opposite versus
(ii) When the force F is increased to F' = 10 N, what is the acceleration?
a = (F'-FF)/m = (10-6)/2 = 2.0 m/sec^2
(iii) What is the speed V, if it accelerates from rest for 10 s?
V = a*t = 2.0*10 = 20 m/sec
