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? asked in Science & MathematicsMathematics · 5 years ago

If sin theta = 0.473, find the value of theta to the nearest degree?

3 Answers

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  • cidyah
    Lv 7
    5 years ago

    sin theta = 0.473

    sin is positive in quadrant 1 and 2

    theta = arcsin(0.473) = 0.49269 radians (28.23 degrees)

    The other solution is pi-0.49269 = 2.6489 radians (151.77 degrees)

    The general solution is:

    theta = 0.49269 + 2n pi (where n is any integer)

    theta = 2.6489 + 2n pi (where n is any integer)

  • Puzzling
    Lv 7
    5 years ago

    Simply compute arcsin(0.473). Usually that is the second function of the sin key on your calculator. Make sure your calculator is in Degree mode.

    sin θ = 0.473

    θ = arcsin(0.473)

    θ ≈ 28.2292099°

    Answer:

    28° (to the nearest whole degree)

    Source(s): https://www.google.com/#q=arcsin(0.473)+in+degrees
  • Como
    Lv 7
    5 years ago

    sin Ө = 0•473

    Ө = 28⁰ , 152⁰-----quadrants 1 and 2

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