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Benjamin
Benjamin asked in Science & MathematicsMathematics · 6 years ago

Calculus!? At what rate is water pouring into the tub if the water level rises at a rate of .8 feet/min?

Update:

Assuming the base of the tub is 18 square feet

2 Answers

Relevance
  • ?
    Lv 6
    6 years ago

    The base area A = 18 ft^2

    Let the height be h = h(t)

    V(t) = A* h(t) , differentiate

    dV/dt = A*dh/dt , but dh/dt = 0.8 ft/min =>

    dV/dt = 18*0.8 = 14.4 ft^3/min

  • Ian H
    Lv 7
    6 years ago

    dV/dt = (base area)* dh/dt= = 18 *0.8 = 14.4 cubic ft/min

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