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? asked in Science & MathematicsPhysics · 7 years ago

Last physics help :D?

A forklift is used to raise a

3.72 m. If the forklift expends

217 kg load from the floor to a height

does it take to lift the load?

1954 W of power, how many seconds



2 Answers

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  • 7 years ago

    Garbbled question... But if I use my detective skills...

    The forklift wants to raise a 217 kg load to a height of 3.72 m. How long does it take using 1954 W of power?

    How much energy does it take to raise 217 kg 3.72 m?

    PE = m*g*h = 217 kg * 9.81 m/s^2 * 3.72 m = 7920 J

    From the definition of power

    P = E/t

    Solve for t

    t = E / P = 7920 J / 1954 W = 4.05 s

  • 7 years ago

    The power describes the amount of work that can be done in one second. According to the power of the forklift, it can do 1954 N * m of work in one second.

    Power = Work ÷ time

    I assume that the forklift is exerting the force that is required to lift the load 3.72 meters at a constant speed. If this is true, the force is equal to the weight of load. And the work is equal to the increase of its potential energy.

    PE = m * g * h = 217 * 9.8 * 3.72 = 7,910.952 J

    1954 = 7,910.952 ÷ time

    Time = 7,910.952 ÷ 1954

    The time is approximately 4.05 seconds.

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