Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Last physics help :D?
A forklift is used to raise a
3.72 m. If the forklift expends
217 kg load from the floor to a height
does it take to lift the load?
1954 W of power, how many seconds

2 Answers
- civil_av8rLv 77 years ago
Garbbled question... But if I use my detective skills...
The forklift wants to raise a 217 kg load to a height of 3.72 m. How long does it take using 1954 W of power?
How much energy does it take to raise 217 kg 3.72 m?
PE = m*g*h = 217 kg * 9.81 m/s^2 * 3.72 m = 7920 J
From the definition of power
P = E/t
Solve for t
t = E / P = 7920 J / 1954 W = 4.05 s
- electron1Lv 77 years ago
The power describes the amount of work that can be done in one second. According to the power of the forklift, it can do 1954 N * m of work in one second.
Power = Work ÷ time
I assume that the forklift is exerting the force that is required to lift the load 3.72 meters at a constant speed. If this is true, the force is equal to the weight of load. And the work is equal to the increase of its potential energy.
PE = m * g * h = 217 * 9.8 * 3.72 = 7,910.952 J
1954 = 7,910.952 ÷ time
Time = 7,910.952 ÷ 1954
The time is approximately 4.05 seconds.