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Chemistry Homework Help?
For each pair, predict which molecule has the greater molar entropy under the same conditions (assume gaseous species):
From Highest S to lowest S.
Ne(g) , F2 (g), & HF(g)
I had put F2, Ne, and then HF because f2 has the most valence electrons and so on, but i got it totally wrong, so im not sure what the answer is.
1 Answer
- 7 years agoFavorite Answer
Hello! Entropy has something to do with the "disorder" in the system. The higher its S, the higher its disorder. Let's start first with the lowest S and that is HF. Among the three, only HF is polar, highly polar, in fact. This strong polarity enables a HF molecule to have stronger attractions for other HF molecules. This hampers disorder in a way since the attraction between them lessens the chaotic movement of the gas molecules. It somehow orders them. F2 has a higher S since it is not a polar molecule. Still, it can attract, though to a much lesser extent, other F2 molecules through London forces, the intermolecular forces of attraction that exist between non-polar molecules. Ne has the highest S since it is monoatomic. It can have London forces; however, since it is smaller than F2, it also has smaller surface area for the attraction to take place.
So from highest S to lowest S: Ne(g) > F2(g) > HF(g)
I hope this helps! God bless! :)
