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Enough of a protonic acid is dissolved in water to produce a 0.0172M solution. The resulting PH is 2.37. find?
find pKa for acid? answer in scientific notation
1 Answer
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- GlenguinLv 77 years agoFavorite Answer
The equilibrium is
HA (aq) <==> H+ (aq) + A- (aq);
Ka = [H+][A-]/[HA]
When the acid is first dissolved, [HA] = 0.0172 M , [H+] = 0, and [A-] = 0.
At equilibrium, [H+] = 10^-2.37 = 4.27x10^-3, [A-] = [H+], and [HA] = 0.0172 - [H+].
Substituting,
Ka = (4.27x10^-3)(4.27x10^-3) / (0.0172 - 4.27x10^-3) = 1.41x10^-3.
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