Factoring Help GRADE 10 MATH HELP!!!!?

Sure. It's just about trial and error.

a) 6.2x^2 + 37.2x - 167.4

6.2(x^2 + 6x - 27)

6.2(x + 9)(x - 3)

b) -3.4x^2 - 40.8x - 108.8

-3.4(x^2 + 12x + 32)

-3.4(x + 8)(x + 4)

c) -3.4x^2 + 17x + 47.6

-3.4(x^2 - 5x - 14)

-3.4(x - 7)(x + 2)

a) 6.2x^2 + 37.2x - 167.4 (factor out 6.2)

= 6.2(x^2 + 6x - 27) = 6.2 (x+ 9)(x - 3)

keep in mind that if the teacher gives you a problem like this, the you can probably simplify the problem.

b) -3.4x^2 -40.8x - 108.8 = -3.4(x^2 + 12x + 32) 3.4(x + 8)(x + 4)

c) -3.4x^2 + 17x + 47.6 = -3.4(x^2 - 5x + 14) = -3.4(x + 2)(x - 7)

Try factoring out each one by the x^2 term such as:

6.2x^2+37.2x-167.4 = 6.2(x^2+6x-27)

Now you need two numbers whose product is -27 and sum is 6 ---> 9 and 3 maybe?

=6.2(x+9)(x-3)

Try like this for the other two

I hope this helps!

Sure you can factor decimals. It's just another coefficient (if it helps think of them as a fraction - tenths)

a) isn't bad once you recognize they are all multiples of 6.2...

6.2(x^2+6x-27)=6.2(x+9)(x-3)

b) -3.4(x^2+12x+32) (if you factor the negative as well it's much easier)

what factors of 32 add up to 12?

c)-3.4(x^2-5x-14)

because the last term is now negative, we need one positive factor of 14 and one negative factor that will add up to -5 (the negative factor will be bigger)

-3.4(x-7)(x+2)