Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

math word problem help please?

A supertanker leaves port traveling north at an average speed of 10 knots. Two hours later a cruise ship leaves the same port, heading south at an average speed of 18 knots. How many hours after the cruise ship sails will the two ships be 209 nautical miles apart? (1 knot = 1 nautical mile per hour, and 1 nautical mile = 1.15 miles)

Update:

please make sure it is in an equation and shows work! thanks!

1 Answer

Relevance
  • 8 years ago
    Favorite Answer

    We can write three different equations from the given information

    #1 = (supertanker distance) = (10 knots)(time)

    #2 = (cruise ship distance) = (18 knots)(time - 2 hours)

    #3 = (supertanker distance) + (cruise ship distance) = 209 nautical miles

    Since #1 + #2 = 209, then

    (10)(time) + (18)(time - 2) = 209

    10time + 18time - 36 = 209

    28time = 209 + 36

    28time = 245

    time = 245/28

    time = 8.75 hours

    /

Still have questions? Get your answers by asking now.