Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.
Buoyancy, fluids, iceberg, physics, etc please help with this quesiton?
an iceberg with a mass 25,00 kg is floating next to your cruis ship in the north atlantic. the density of ice is 0.920 g/cm^3 , the density f seawater is 1.03 g/cm^3 and the density of freshwater is 1.00 g/m^3. the mass of a proton or neutron is 1.67x10^-27 kg
1) what is the buoyant force on the iceberg?
2) what fraction of the iceberg is above water?
3) calculated the number density of ice and freshwater and compare them
1 Answer
- WoodsmanLv 79 years agoFavorite Answer
1) The bouyant force on the berg is equal to its weight (since it's floating):
Fb = mg = 25kg * 9.8m/s² = 245 N
2) The volume of the berg is Vb = m / ρ = 25kg / 920kg/m³ = 0.027 m³
The volume of displaced water is Vw = 25kg / 1030kg/m³ = 0.024 m³
Fraction above water is 1 - .024/.027 = 0.107 ≈ 1/9
3) ice: n = 920kg/m³ * 1neutron/1.67e-27kg = 5.51e29 neut/m³
freshwater: n = 1000kg/m³ * 1neutron/1.67e-27kg = 5.99e29 neut/m³
number density of freshwater is almost 10% higher than that of ice
