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physics help!!! please!!!! someone?
on sledding hill the sledding slope has an incline of about (theta). assume the coefficient of kinetic friction between the sled and ice is mu and that there is not too much friction to slide
Calculate the acceleration of the sled as a function of the acceleration of free fall g, the angel of the incline theta, and the coefficient of the kinetic friction mu.
1 Answer
- JánošíkLv 79 years agoFavorite Answer
The total force of the sled is
F = m × g
The force perpendicular to the hill is equal to the normal force is
Fn = F × cos(θ)
Fn = m × g × cos(θ)
The force of friction is
Ff = μ × Fn
Ff = μ × m × g × cos(θ)
The force parallel to the hill is
Fp = F × sin(θ)
Fp = m × g × sin(θ)
The net force on the sled is
Fnet = Fp - Ff
Fnet = m × g × sin(θ) - μ × m × g × cos(θ)
Fnet = m × g × (sin(θ) - μ × cos(θ))
The acceleration of the sled is
a = Fnet / m
a = m × g × (sin(θ) - μ × cos(θ)) / m
a =g × (sin(θ) - μ × cos(θ))
