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physics question pleassseeeee help!?
on sledding hill the sledding slope has an incline of about (theta). assume the coefficient of kinetic friction between the sled and ice is mu and that there is not too much friction to slide
Calculate the acceleration of the sled as a function of the acceleration of free fall g, the angel of the incline theta, and the coefficient of the kinetic friction mu.
1 Answer
- ?Lv 79 years agoFavorite Answer
Normal force is
Fn = mgcosθ
Friction force is
Ff = μFn
Ff = μmgcosθ
Which is the force restricting accelerating down hill
The force accelerating the sled down hill is
Fa = mgsinθ
The net force is
F = Fa - Ff
F = mgsinθ - μmgcosθ
F = mg(sinθ - μcosθ)
From Newton
F = ma
we can then see that the net acceleration is
a = g(sinθ - μcosθ)
