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Lv 7
2.287g of a metallic oxide is reduced with excess H, 1.054g of the metal is produced. Find the metallic oxide.?
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- BobbyLv 79 years agoFavorite Answer
mass of metal = 1.054 g
mass of metal oxide = 1.187g
mass of O = 1.187 - 1.054 = 0.133 g or .133 / 16 moles of O = 0.008313 moles
If the metal oxide is M2O the moles of M = 0.008313 x 2 moles
molar mass of M = 1.054/ 0.01663
= 63.40 g / mol .. copper
it helps if you give the correct data
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