Yahoo Answers is shutting down on May 4th, 2021 (Eastern Time) and the Yahoo Answers website is now in read-only mode. There will be no changes to other Yahoo properties or services, or your Yahoo account. You can find more information about the Yahoo Answers shutdown and how to download your data on this help page.

Pope
Lv 7
Pope asked in Science & MathematicsMathematics · 1 decade ago

Can you keep this proof on the students' level?

This is something that came from an exercise book. Some students got stuck on this advanced problem. I can do the proof, but for sake of the students, I would like to find a simpler and shorter way. They have strong algebra skills, and they are getting good with elementary trigonometry identities, but they have had no double angle formulas and no calculus at all.

This is what they have proved so far:

sinθcosθ = k

(sinθ + cosθ)² = 1 + 2k

(sinθ - cosθ)² = 1 - 2k

Now prove this inequality:

-1/2 ≤ k ≤ 1/2

2 Answers

Relevance
  • Hemant
    Lv 7
    1 decade ago
    Favorite Answer

    (1+2k) ≥ 0 ∴ 0 ≤ ( 1 + 2k ) ∴ -1 ≤ 2k ∴ (-1/2) ≤ k ........ (1)

    (1-2k) ≥ 0 ∴ 1 ≥ 2k ∴ (1/2) ≥ k ∴ k ≤ (1/2) ................... (2)

    Writing (1) and (2) together,

    (-1/2) ≤ k ≤ (1/2) ............................. Q.E.D.

    ________________________

  • satszn
    Lv 6
    1 decade ago

    -1<=sin2A<=1 , -1<2sinAcosA<1 , -1/2<sinAcosA<1/2 , -1/2<k<1/2

Still have questions? Get your answers by asking now.