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why is it that two equals one?
X^2 - X^2 = X^2 - X^2
a little rearrange
(X+X)(X-X)= X(X-X)
divide out the common term
X+X = X
let X =1
and then
2 = 1
9 Answers
- 1 decade ago
The problem happens after the equation is rearranged.
(X+X)(X-X) = X(X-X)
The common term is (X-X). However, (X-X) equals zero. Division by zero is not allowed, so the common term cannot be divided out.
Therefore the line X+X=X is not correct. And, 2 does not equal 1.
- Anonymous1 decade ago
(x+x)*(x-x) is not equal to x*(x-x) but it is equal to x^2-x^2+x^2-x^2, which is equal to 0
because
if x = 1
1^2 - 1^2 + 1^2 - 1^2 = 1 - 1 + 1 - 1 = 0 + 0 = 0
- Anonymous1 decade ago
In the second line (X-X)=0 so dividing by anything is meaningless.
- 1 decade ago
you didnt rearrange it right. you added x+x to one side and then only x to the other. you should do the same to both sides in every algebraic equation
hope this helps & have a great day!!! :D
- 1 decade ago
your second step is wrong, -x^2 cant be rearranged into (x-x) and x^2 cant be (x+x)
- a_nobodyLv 51 decade ago
you boogered up on your rearrange part, squaring involves multiplication of X, we can't use repeated addition