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chemistry please helpppppppppppppppppppppppppp?
convert the following:
8.4g/L NaCl into mM
3.16*10^-6 M Fe2+ into ppm
6.30 mM glucose into mg/dL
5.0 ppm Ca2+ into muM
1 Answer
- Old Science GuyLv 71 decade agoFavorite Answer
8.4 g/L / 58.5 g/mol * 1000 mmol/mol = _____ mmol.L = _____ mM
3.16E-6 M you would have to assume that the rest of the solution is water so that you could change 1 L of water into moles (about 55.56)
3.16E-6 mol Fe2+ / 55.56 mol solution = 5.69E-8 part Fe2+/part solution
then multiply by 1E6 to get ppm (0.0569 ppm)
6.30 mmol/L * 342 mg/mmol * 1 L/10 dL = 215 mg/dL
5.0 mol Ca2+/1E6 mol solution * 1E6 muM/mol * 55.56 mol/L = 278 muM
(same reasoning as second problem - just in reverse)
better check my numbers, etc.
