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If 6.53 g of water are present, how many molecules are present?
1 Answer
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- geek.....Lv 71 decade agoFavorite Answer
given: 6.53 g H2O
want: x molecules H2O
know: Nav=6.02 x10^23 molecules
step 1: start with g given, go to mol, go to Nav
step 2: check ans
6.53 g H2O x(mol H2O/18.02 g H2O) x(6.02 x10^23 molecules H2O/mol H2O)= 2.18 x10^23 molecules H2O
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