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Derivative of cos^2(x^2-2)?
A little unsure on how to do this one. Would I have to combine the chain and product rules? If so, the answer would be (2cos)(-sin)(x^2-2)+(2x)(cos^2)?? Is that anywhere near correct? Thanks.
2 Answers
- MicoLv 41 decade agoFavorite Answer
use the chain rule:
[cos(x²-2)]²
now let u = cos(x²-2)
d/du u² = 2u
2u * d/dx cos(x²-2)
2cos(x²-2) * d/dx cos(x²-2)
use the chain rule again:
let u = x²-2
d/du cos(u) = -sin(u)
2cos(x²-2) [-sin(u)] * d/dx (x²-2)
-2cos(x²-2) sin(x²-2) (2x)
-4x cos(x²-2) sin(x²-2)
- 1 decade ago
Have a problem with your question, because don´t exist this cos^2(x^2-2), but can exist cos2^(x^2-2). Answer this and I can answer your question...
