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Calculus Question With Differential Equation and Exponential Function?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Please include the steps in solving for x(1), given that x(0) = 0, v(0) = 2, and a(t) = 4x(t). . Set up the equation for x(t) and solve for x(1). We know x'(t) = v(t); x"(t) = x(t).
The answer is x(1) = 1/2 (e^2 - e^-2). Show steps. Thank you.
Mathematics2 years agoCalculus Question With Differential Equation and e Function?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Please include the steps in solving for x(1), given that x(0) = 0, v(0) = 2, and a(t) = 4x(t). . Set up the equation for x(t) and solve for x(1). We know x'(t) = v(t); x"(t) = x(t).
The answer is x(1) = 1/2 (e^2 - e^-2). Show steps. Thank you.
Mathematics2 years agoCalculus Question Involving Exponential Function?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Please include the steps in solving for x(1), given that x(0) = 0, v(0) = 2, and a(t) = 4x(t). The answer is x(1) = 1/2 (e^2 - e^-2). x"(t) = a(t); v(t) = x'(t); set up the equation for x(t) and solve for x(1).
Mathematics2 years agoCalculus Question Involving Exponential Function?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Please include the steps in solving for x(1), given that x(0) = 0, v(0) = 2, and a(t) = 4x(t). The answer is x(1) = 1/2 (e^2 - e^-2). x"(t) = a(t); v(t) = x'(t); set up the equation for x(t) and solve for x(1).
Mathematics2 years agoCalculus Question Using The Exponential Function?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Please include the steps in solving for x(1), given that x(0) = 0, v(0) = 2, and a(t) = 4x(t). The answer is x(1) = 1/2 (e^2 - e^-2). x"(t) = a(t); v(t) = x'(t); set up the equation for x(t) and solve for x(1).
Mathematics2 years agoCalculus Problem Solving With The Exponential Function e - Please Help! ?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Please include the steps in solving for x(1), given that x(0) = 0, v(0) = 2, and a(t) = 4x(t). The answer is x(t) = 1/2 (e^2 - e^-2).
Please set up x"(t), x'(t), x(t) and use e function. Thank you.
Personal Finance2 years agoSolve x(1) = 1/2 (e^2 - e^-2) - Given Details Below?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Please find and include the steps to
x(1), given that x(0) = 0, v(0) = 2, and a(t) = 4x(t).
The answer is x(t) = 1/2 (e^2 - e^-2).
I just can't set the problem up. I'm hoping someone can solve this for me. Thank you so very much and have a great day!
Mathematics2 years agoCalculus Question Involving The Exponential Function e?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Please find and include the steps to
x(1), given that x(0) = 0, v(0) = 2, and a(t) = 4x(t).
The answer is x(1) = 1/2 (e^2 - e^-2).
I just can't set the problem up. I'm hoping someone can solve this for me. Thank you so very much and have a great day!
Mathematics2 years agoCalculus Question Involving Exponential Function e?
2 AnswersMathematics2 years agoCalculus Question Involving Exponential Function e?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Find x(1) given that x(0) = 0, v(0) = 2 and a(t) = 4x(t). The answer is x(1) = 1/2 ( e^2 - e^-2) Please show all steps in arriving at the answer. Thank you.
Mathematics2 years agoCalculus Problem Using Exponential Function e?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Find
(a) x(1) given that x(0) = 0, v(0) = 2 and a(t) = 4x(t).
The answer is x(1) = 1/2 ( e^2 - e^-2)
Please show all steps in arriving at the answer. Thank you.
1 AnswerMathematics2 years agoProblem Involving Exponential Function?
A particle moves along a coordinate line so that at time t it has coordinate x(t), velocity v(t), and acceleration a(t). Find
(a) x(1), given that x(0) = 0, v(0) = 2 and a(t) = 4x(t). Please include step-by-step in arriving at the answer.
The answer is x(t) = 1/2 ( e^2 - e^-2).
Thank you so much for your help. I appreciate your time.
Mathematics2 years agoCalculus Question on Limits: Give an epsilon, delta proof for the following limit:?
The limit of f(x) = x^2 as x approaches 2 = 4
If 0 < { x - 2 } < delta, then { x^2 - 4 } < epsilon.
Please show all steps. What is the minimum value of delta? Does the square root of epsilon work?
Thank you - I can't seem to set up the proof correctly.
3 AnswersMathematics7 years agoUsing the Axiom of Induction - Show that the following statement holds for each positive integer n?
1^3 + 2^3 + 3^3 + + + n^3 = (1 + 2 + 3 + + + n)^2
Hint: Use 1 + 2 + 3 + + + n = (1/2)n(n + 1)
Please show all steps. Thank you very much.
2 AnswersMathematics7 years agoCalculus Question: Find the volume of a solid enclosed by the following surface?
z^2 = ( x^2 + y^2 ) (x^2 + y^2 + z^2 )^3
Use spherical coordinates.
The answer is = 2pi/3
Thank you very much.
1 AnswerMathematics7 years agoCalculus Question: Find the centroid of the triangle with vertices (a1,a2), (b1,b2), (c1,c2) - PLEASE HELP!?
The vertices are (a1,a2), (b1,b2), (c1,c2). I understand that the geometric concept of the centroid is where the intersection of the three medians inside of the triangle from the vertices to the middles of the opposites sides occurs.
However....the proof I'm looking for must involve using double integration with lower & upper limits.
I know that deriving the centroid involves multiplying the double integrals by the reciprocal of the area of the plane of the triangle. I can't seem to set up the triangle correctly and solve this using the vertices as provided. I realize that solving this is a laborious process...sorry. However...
The answer is a1 + b1 + b3 / 3 + a2 + b2 + c3 / 3 . Please show all steps.
Thank you for your time.
1 AnswerMathematics7 years ago